Math
posted by Marcus .
An object is thrown upward from the top of a 160foot building with an initial velocity of 144 feet per second. The height, h, of the object after t seconds is given by the equation h=16t^2+144t+160. When will the object hit the ground?
The object will hit the ground when the time is _____ seconds.

when it hits the ground, h = 0
so solve:
16t^2 + 144t + 160 = 0
divide each term by 16
t^2  9t  10 = 0
easy to solve, use factoring.
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