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An object is thrown upward from the top of a 160-foot building with an initial velocity of 144 feet per second. The height, h, of the object after t seconds is given by the equation h=-16t^2+144t+160. When will the object hit the ground?

The object will hit the ground when the time is _____ seconds.

  • Math -

    when it hits the ground, h = 0
    so solve:

    -16t^2 + 144t + 160 = 0
    divide each term by -16

    t^2 - 9t - 10 = 0

    easy to solve, use factoring.

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