math
posted by Melvin .
How much water must be added to 60 liters of 60 percent alcohol mixture to reduce it to a mixture of 50 percent alcohol concentration? What if 30 percent alcohol mixture is added instead of water?

(60 * .6) + (x * 0) = (60 + x) * .5
(60 * .6) + (x * .3) = (60 + x) * .5
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How much water must be added to 60 liters of 60 percent alcohol mixture to reduce it to a mixture of 50 percent alcohol concentration?