Chemistry 131

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4.0g of an unknown potassium halide (KX, where X is the halide) is dissolved in 100g of water. The solution freezes at -1.28 degrees Celsius. What is the identity of the halide?

  • Chemistry 131 -

    freezingpt=-l.86*2*4/molmass*1/.1
    molmass=l.86*8*10/1.28=116.3
    mass of K is 39
    so atomic mass of halide is 77, potassium bromide.


    do the math a little more carefully than I did in my head.

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