PreCalc

posted by Anthony

When the polynomial p(x) is divided by (x–2), the remainder is 3 and when p(x) is divided by (x+1) the remainder is 9. Given that p(x) may be written in the form (x–2)(x+1)q(x) + Ax + B where q(x) is a polynomial and A and B are numbers, find the remainder when p(x) is divided by (x–2)(x+1).

  1. Anthony

    Can someone please actually help?

  2. Steve

    impatient much? We don't all just sit by our computers all day waiting for postings. We also have lives.

    we are given
    p(2) = 3
    p(-1) = 9

    so, using those values (and recognizing that the (x–2)(x+1)q(x) part is zero),

    2A+B = 3
    -A+B = 9

    solve for A and B, and Ax+B is the remainder.

  3. Anthony

    Steve,

    My apologies but the only reason I said that was because some random person kept spamming this question with random sayings and it kinda got annoying. I didn't mean to offend you in any way

  4. Steve

    yeah, that happens some here.

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