PreCalc
posted by Anthony .
When the polynomial p(x) is divided by (x–2), the remainder is 3 and when p(x) is divided by (x+1) the remainder is 9. Given that p(x) may be written in the form (x–2)(x+1)q(x) + Ax + B where q(x) is a polynomial and A and B are numbers, find the remainder when p(x) is divided by (x–2)(x+1).

PreCalc 
Anthony
Can someone please actually help?

PreCalc 
Steve
impatient much? We don't all just sit by our computers all day waiting for postings. We also have lives.
we are given
p(2) = 3
p(1) = 9
so, using those values (and recognizing that the (x–2)(x+1)q(x) part is zero),
2A+B = 3
A+B = 9
solve for A and B, and Ax+B is the remainder. 
PreCalc 
Anthony
Steve,
My apologies but the only reason I said that was because some random person kept spamming this question with random sayings and it kinda got annoying. I didn't mean to offend you in any way 
PreCalc 
Steve
yeah, that happens some here.
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