posted by Anthony
When the polynomial p(x) is divided by (x–2), the remainder is 3 and when p(x) is divided by (x+1) the remainder is 9. Given that p(x) may be written in the form (x–2)(x+1)q(x) + Ax + B where q(x) is a polynomial and A and B are numbers, find the remainder when p(x) is divided by (x–2)(x+1).
Can someone please actually help?
impatient much? We don't all just sit by our computers all day waiting for postings. We also have lives.
we are given
p(2) = 3
p(-1) = 9
so, using those values (and recognizing that the (x–2)(x+1)q(x) part is zero),
2A+B = 3
-A+B = 9
solve for A and B, and Ax+B is the remainder.
My apologies but the only reason I said that was because some random person kept spamming this question with random sayings and it kinda got annoying. I didn't mean to offend you in any way
yeah, that happens some here.