What is the equation of a line that is perpendicular to 2x+y=−4 and passes through the point (2, −8)
my answer:
1/2x-9
AM I CORRECT OR NO ???
i mean y=1/2x-9
nope, your slope is right, but when I substituted x = 2, I got
y = (1/2)(2) - 8
= 1 - 8
= -7
so the point does not lie on your line.
Furthermore, since the original equation was written in standard form, I think the same style of equation would be expected.
so its y=1/2x-7?
Your equation was correct.
For some reason I wrote down your equation as
y = 1/2x-8 to do my calculation,
and I then carried through the calculations with my typo.
yes, it is y = (1/2)x - 9
thnk you !
No, your answer is not correct. The equation of a line that is perpendicular to another line can be found by following these steps:
1. Find the slope of the given line. To do this, rearrange the equation of the given line into slope-intercept form (y = mx + b) where m is the slope.
Given line: 2x + y = -4
Rearranging, we have y = -2x - 4
So the slope of the given line is -2.
2. The slope of a line perpendicular to another line is the negative reciprocal of the slope of the given line. In this case, the negative reciprocal of -2 is 1/2.
3. Use the point-slope form of a line (y - y1) = m(x - x1), where (x1, y1) is the given point and m is the slope of the line.
Using the point (2, -8):
y - (-8) = 1/2(x - 2)
Simplifying, we get:
y + 8 = 1/2(x - 2)
or
y = 1/2(x - 2) - 8
This is the equation of the line that is perpendicular to 2x + y = -4 and passes through the point (2, -8).