A football stadium holds a maximum of 1000 fans. Adult tickets cost $5 each and
child tickets cost $2 each. The football club needs to raise at least $3000 to cover
costs. The football club aims to sell at least one child ticket for two adult tickets
sold Let x = number of child tickets sold and y = number of adult tickets sold.
Find the inequalities
obviously
x + y ≤ 1000
and just as clearly:
2x + 5y ≥ 3000
Now show me the efforts you made in the next problem.
To find the inequalities, we need to consider the conditions given in the problem.
1. The stadium holds a maximum of 1000 fans.
This means that the total number of both adult and child tickets sold cannot exceed 1000.
So we can write the inequality:
x + y ≤ 1000
2. The football club needs to raise at least $3000 to cover costs.
The total amount raised from selling adult tickets is given by 5y (since each adult ticket costs $5).
The total amount raised from selling child tickets is given by 2x (since each child ticket costs $2).
To cover costs, the total amount raised should be at least $3000.
So we can write the inequality:
5y + 2x ≥ 3000
3. The football club aims to sell at least one child ticket for every two adult tickets sold.
This means that for every 2 adult tickets sold (y), at least one child ticket (x) must be sold.
So we can write the inequality:
x ≥ y/2
Therefore, the inequalities are:
x + y ≤ 1000
5y + 2x ≥ 3000
x ≥ y/2