posted by P .
A solid ball of mass 2 kg, rolls down a hill that is 6 meters high. What is the rotational KE at the bottom of the hill?
This is a little complicated, it is rolling, and translating .
let translational velocity be v.
translational KE=1/2 m v^2=1/2 m w^2r^2
rotational KE= 1/2 I w^2=1/2*2/5 mr^2*w^2
but total energy=sum of above
solving for v
and then rotational KE= .2*m*v^2
check all that.