What is the molar mass of an acid if 0.422 g of the acid are neutralized by 17.5 mL of 0.268 M NaOH?
No. To start, you don't have enough information to answer because the problem doesn't tell you if the acid is monoprotic, diprotic, triprotic, etc. If you assume it is monoprotic, it is done this way.
HA + NaOH ==> NaA + H2O
mols NaOH = M x L = 0.268 x 0.0175 = approx 0.0047 but that's just an estimate and you must recalculate for a better answer. Then mols = grams/molar mass or 0.047 = 0.422/molar mass and solve for molar mass of approx 90. But if diprotic, then H2A + 2NaOH ==> Na2A + 2H2O.
mols NaOH = M x L = approx 0.0047
mols H2A = 0.0047 mols NaOH x (1 mol H2A/2 mols NaOH - 0.0047/2 = approx 0.0024 mols H2A. Then molar mass = 0.422/0.0024 = approx 180. Triprotic acid is done similarly.
"it" or "jan" or whatever name you use, you need to stop posting answers since you don't know the subjects well enough.
To find the molar mass of the acid, we can use the concept of balanced chemical equations and stoichiometry. Here's how you can approach this problem:
1. Write the balanced chemical equation for the neutralization reaction between the acid and NaOH. For example, let's assume the reaction is as follows:
Acid (HA) + NaOH → H2O + NaA
2. Determine the number of moles of NaOH used in the reaction. To do this, calculate moles using the given concentration and volume of NaOH:
moles NaOH = concentration NaOH (M) × volume NaOH (L)
In this case: moles NaOH = 0.268 M × 0.0175 L
3. Use the balanced equation to determine the stoichiometric ratio between the acid and NaOH. In this case, the ratio is 1:1, meaning 1 mole of NaOH reacts with 1 mole of acid.
4. Since the ratio is 1:1, the moles of NaOH used are equal to the moles of the acid present initially.
5. Convert the moles of acid to grams using the given mass:
mass acid (g) = moles acid × molar mass acid
In this case: mass acid = 0.422 g
6. Rearrange the formula from step 5 to solve for the molar mass of the acid:
molar mass acid = mass acid (g) / moles acid
7. Substitute the values into the equation from step 6 to calculate the molar mass of the acid.
What is the molar mass of an acid if 0.422 g of the acid are neutralized by 17.5 mL of 0.268 M NaOH?
NAOH:
0.268*1000/17.5=15.3
Acid:0.422/0.268=1.57 mr
I think