Question

Ax+b6=a-b

Bx-ay=a+b. xy maan se

Answer 1

Not sure what you mean, but I'll guess

Ax+By = a-b
Bx-Ay = a+b

ABX+B^2y = B(a-b)
ABX-A^2y = A(a+b)

(B^2-A^2)y = B(a-b)-A(a+b)

y = (B(a-b)-A(a+b))/(B^2-A^2)
Now you can find x.

If that's not what you had in mind, you'd better explain it a bit better.