The width of a rectangular garden is 2 feet more than 1/3 of its length. The perimeter is 52 feet. Find the dimensions of the rectangle.

P = 2L + 2W

52 = 2L + 2(1/3L + 2)

52 = 2L + 2/3L + 4

52 = 2 2/3L + 4

48 = 8/3L

48/(8/3) = L

48 * (3/8) = L

144/8 = 18 = L

Thank you Ms. Sue!!!

You're welcome, Shelby.

Yes, I posted part of the answer and she already thanked me.

To find the dimensions of the rectangle, we can set up equations based on the given information.

Let's assume that the length of the rectangular garden is represented by the variable 'L', and the width is represented by the variable 'W'.

According to the problem, the width of the garden is 2 feet more than 1/3 of its length. Mathematically, this can be expressed as:

W = (1/3)L + 2

The perimeter of a rectangle can be calculated by adding all the sides. In this case, we have two sides of length L and two sides of length W. Thus, the perimeter is given by:

Perimeter = 2L + 2W

We are given that the perimeter of the garden is 52 feet, so we can substitute these values into the equation:

52 = 2L + 2W

Now, we can substitute the expression W = (1/3)L + 2 into the equation:

52 = 2L + 2((1/3)L + 2)

Simplifying this equation will allow us to solve for the dimensions of the rectangular garden.