posted by Mart .
A physics student kicked a soccer ball toward an aprtment building 40.8 meters from her. The velocity of the ball was 40 m/s^2 @30 degrees. At what approximate height did the ball hit the building?
initial vertical velocity = Vi=40 sin 30 = 20 m/s (not m/s^2)
constant horizontal velocity = 40 cos 30
How long to get there?
40.8 m/(40 cos 30) = 1.18 seconds
so now the vertical problem, how high after 1.18 s
h = Vi t - (1/2) g t^2
h = 20(1.18) -4.9(1.18)^2
all yours :)