Chemistry Help

posted by .

For the reaction 2HI(g) <----> H2(g) + I2(g),
Kc = 0.0198 at 721K. What is the HI concentration at 721K if [H2] = 0.120 M and [I2] = 0.0150 M?

I'm getting .303 M but that's not one of the options.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    Can someone explain this to me? In the reaction: --> AgCl(s)<_______ Ag+(aq) + Cl-(aq) the shorter arrow pointing to the right shows that the qe. mixture consists mostly of ______. ---> In the reaction HC2h302 + H20<_______
  2. Chemistry check my answer?

    Hi! is my answer correct? Consider the following chemical reaction: H2 (g) + I2 (g) <> 2HI (g) At equilibrium in a particular experiment, the concentrations of H2, I2, and HI were 0.15 M, 0.033 M, and 0.55 M, respectively. The
  3. Chemistry II

    At a certain temperature, Kc = 33 for the reaction: H2(g) + I2(g) 2HI(g) Assume that the initial concentrations of both H2 and I2 are 6.00 x 10-3 mol/L. Find the concentration of each reactant and product at equilibrium.
  4. chemistry

    In a reaction A to products, ,4.40 min after the reaction is started concentration of A is 0.588M. The rate of reaction at this point is rate= -change in concentration of A/change in time=2.2x10^-2Mmin^-1. Assume that this rate remains …
  5. chem12

    for the equilibrium 2HI(g)--- H2(g) + I2 k eq = 8.0 2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases. Inital 2HI 0.5mol/l H2 =0 …
  6. chem 12

    for the equilibrium 2HI(g)--- H2(g) + I2 k eq = 8.0 2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases. Inital 2HI 0.5mol/l H2 =0 …
  7. chem12

    2HI(g)--H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= -2x …
  8. chem12

    2HI(g)--H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= -2x …
  9. chemistry

    The decomposition of hydrogen iodide if the equation: 2HI (g)--> H2 (g) + I2 (g) The reaction is second order and has a constant rate equal to 1, 6X10^-3 L/mol * s at 700 degrees. If the initial HI concentration in a vessel is 3.4X10 …

More Similar Questions