Calculus
posted by Devin
In a 21 meter race between a turtle and a hare, the turtle leaves 8 minutes before the hare. The hare, by running at an average speed of 0.5 meters per hour faster than the turtle, crosses the finish line 4 minutes before the turtle. What are the average speeds of the turtle and the hare?

Steve
since time = distance/speed, if the turtle's speed is x m/min, then since .5 m/hr = 1/120 m/min
21/x = 8 + 21/(x+1/120) + 4
The turtle moves at 7/60 m/min = 7 m/hr
The hare moves at 1/8 m/min = 7.5 m/hr
you can check the times to verify that they work out.
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