Can someone help me find the grams of what I produced. This is my first experiment I've ever done before and it was fun.
Na2CO3 + 2HCl = 2NaCl + H2O + CO2
Empty crucible is: 33.076g
I Started with 0.575 Na2CO3
How do I set this up to find how much NaCl that I produced with a Stoichiometry problem?
To find the amount of NaCl that you produced using stoichiometry, you need to follow these steps:
Step 1: Determine the molar mass of Na2CO3.
The molar mass of Na2CO3 is calculated by adding the atomic masses of each element:
Na (sodium) = 22.99 g/mol
C (carbon) = 12.01 g/mol
O (oxygen) = 16.00 g/mol
So, the molar mass of Na2CO3 is:
2(22.99 g/mol Na) + 12.01 g/mol C + 3(16.00 g/mol O) = 105.99 g/mol
Step 2: Calculate the number of moles of Na2CO3.
To find the moles of Na2CO3, divide the mass of Na2CO3 by its molar mass:
0.575 g Na2CO3 / 105.99 g/mol = 0.0054 mol Na2CO3
Step 3: Use the balanced chemical equation to determine the stoichiometric ratio.
From the balanced equation, we know that 1 mole of Na2CO3 reacts with 2 moles of HCl to produce 2 moles of NaCl.
Step 4: Convert moles of Na2CO3 to moles of NaCl.
Multiply the moles of Na2CO3 by the stoichiometric ratio:
0.0054 mol Na2CO3 * (2 mol NaCl / 1 mol Na2CO3) = 0.0108 mol NaCl
Step 5: Convert moles of NaCl to grams.
To find the mass of NaCl, multiply the moles of NaCl by its molar mass:
0.0108 mol NaCl * (58.44 g/mol NaCl) = 0.631 g NaCl
Therefore, you produced approximately 0.631 grams of NaCl in your experiment.