solve the quadratic equation 2x^4-3x^3-7x^2 12x-4=0
well, if you meant
2x^4-3x^3-7x^2+12x-4, it is a quartic, but can easily be factored into two quadratic factors.
It is (x^2-4)(2x^2-3x+1)
which are both easily solved.
2x^4-3x^3-7x^2+12x-4, it is a quartic, but can easily be factored into two quadratic factors.
It is (x^2-4)(2x^2-3x+1)
which are both easily solved.