if an owl regurgitates an average of 2 pellets a day and the average number of prey in one pellet is 4, how many rodents could be eliminated in one year? (assume there are 365 days a year)

2 * 4 * 365 = ?

2,920 rodents

Thanks so much! :)

You're welcome.

To calculate the number of rodents that could be eliminated in one year, we need to multiply the number of pellets regurgitated per day by the number of prey in each pellet, and then multiply that by the number of days in a year.

1. Calculate the number of prey eliminated per day:
Number of prey in one pellet = 4
Number of pellets regurgitated per day = 2

Number of prey eliminated per day = Number of prey per pellet x Number of pellets per day
= 4 x 2
= 8

2. Calculate the number of prey eliminated in one year:
Number of days in a year = 365

Number of prey eliminated in one year = Number of prey eliminated per day x Number of days in a year
= 8 x 365
= 2920

Therefore, an owl could potentially eliminate approximately 2,920 rodents in one year.