Find the ratio of the coulomb electrical force to the gravitation force between two electrons .
google is your friend.
Try
http://www.batesville.k12.in.us/physics/PhyNet/e%26m/electrostatics/michaels_question.htm
Steve wowowowowow xD
To find the ratio of the coulomb electrical force to the gravitation force between two electrons, we first need to calculate each force individually.
The coulomb electrical force between two charged objects can be calculated using Coulomb's law: F = k * ((q1 * q2) / r^2), where F is the force between the objects, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the electrostatic constant (k = 8.988 × 10^9 N m^2/C^2).
For two electrons, the magnitude of their charge is known to be 1.6 × 10^-19 C each.
On the other hand, the gravitation force between two objects can be calculated using Newton's law of gravitation: F = G * ((m1 * m2) / r^2), where F is the force between the objects, m1 and m2 are the masses of the objects, r is the distance between the objects, and G is the gravitational constant (G = 6.67430 × 10^-11 N m^2/kg^2).
The mass of an electron is approximately 9.11 × 10^-31 kg.
Now, substituting the values into the formulas:
Coulomb electrical force (Fe) = k * ((1.6 × 10^-19 C) * (1.6 × 10^-19 C) / r^2)
Gravitation force (Fg) = G * ((9.11 × 10^-31 kg) * (9.11 × 10^-31 kg) / r^2)
To calculate the ratio, divide Fe by Fg:
Ratio = Fe / Fg
Keep in mind that the value of r (distance between the electrons) should be known or assumed in order to obtain an accurate ratio.