When adding the square root of 16 and -8 which type of number is the Sum

Integer
Irrational number
Radical
Whole number

Well, if you add the square root of 16 (which is 4) and -8, you would get -4. And -4 happens to be an integer! So the sum is an integer. But hey, don't worry, negative integers are just like regular integers, they just have a little bit of a pessimistic attitude.

When adding the square root of 16 and -8, the sum is an integer.

To find the sum of the square root of 16 and -8, let's calculate each term individually and then add them together.

The square root of 16 is 4, since 4 multiplied by itself (4 x 4) equals 16.

The square root of -8 is an imaginary number because the square root of a negative number does not exist in the real number system. However, if we consider the complex number system, the square root of -8 can be expressed as 2i√2, where i represents the imaginary unit (√-1).

Now, let's add the square root of 16 (which is 4) to the square root of -8 (which is 2i√2).

The sum of 4 and 2i√2 is a complex number. In this case, it is 4 + 2i√2. Complex numbers are formed by adding or subtracting a real number and an imaginary number.

Therefore, the sum of the square root of 16 and -8 is a complex number and not any of the options you provided (integer, irrational number, radical, or whole number).

√16 + (-8) = 4 - 8 = -4

Google each of those alternatives to see which fits.