a single ball is drawn from an urn containing 6 balls numbered 1 through 6. Find the probability that the ball choose as follows.

an even-numbered ball or an odd-numbered ball

To find the probability of drawing either an even-numbered ball or an odd-numbered ball, we need to determine the total number of favorable outcomes and the total number of possible outcomes.

In this case, the favorable outcomes are the balls that are either even-numbered or odd-numbered. Let's calculate each separately:

1. Even-numbered balls: The even-numbered balls are 2, 4, and 6. So, there are 3 even-numbered balls.

2. Odd-numbered balls: The odd-numbered balls are 1, 3, and 5. So, there are also 3 odd-numbered balls.

Now, let's calculate the total number of possible outcomes. Since we are drawing a single ball, there are 6 possible balls to choose from.

To calculate the probability, we divide the number of favorable outcomes by the number of possible outcomes:

P(Even or Odd) = (Number of Even or Odd balls) / (Total number of balls)

P(Even or Odd) = (3 + 3) / 6

P(Even or Odd) = 6 / 6

P(Even or Odd) = 1

Therefore, the probability of drawing either an even-numbered ball or an odd-numbered ball is 1, which is equivalent to 100%.

1/2

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