Math

posted by Promise

The average travel time to work for a person living and working in​ Kokomo, Indiana is 17 minutes. Suppose the standard deviation of travel time to work is 4.5 minutes and the distribution of travel time is approximately normally distributed.
What is the travel time to work that separates the bottom​ 2.5% of people with the median or​ 50%? Round to the nearest tenth of a minute.

1. PsyDAG

50% in a normal distribution = median = mean

Z = (score-mean)/SD

Look in the back of your statistics textbook for a table called something like “area under normal distribution” to find the proportion/probability (.025) and its Z score. Insert into equation above and solve for score.

Subtract one score from the other.

2. Promise

Im still not understanding

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