A train slows down as it rounds a sharp horizontal turn, going from 90 km/h to 54 km/h in the 15.0 it takes to round the bend. Compute the acceleration at the moment the train reaches 50.0 km/h. Assume the train continues to slow down at this time in the same rate.
I need help finding the radius.
Thanks
I don't know for certain what round the bend means. If you knew it was a 90 degreebend, then you have the time (15sec) it takes to go 1/4 a circle, and the average speed, so you could compute the radius, however, round the bend to me doesn't imply a right turn.
I can't figure radius from what is given.
To find the radius of the turn, you can use the known values of the initial speed (90 km/h), final speed (50 km/h), and the time it takes to round the bend (15.0 s).
First, let's convert the speeds from km/h to m/s:
Initial speed = 90 km/h = (90 * 1000 m) / (3600 s) = 25 m/s
Final speed = 50 km/h = (50 * 1000 m) / (3600 s) = 13.89 m/s
Now, we can calculate the acceleration using the formula:
Acceleration (a) = (Final speed (vf) - Initial speed (vi)) / Time (t)
Plugging in the values:
Acceleration = (13.89 m/s - 25 m/s) / 15.0 s
Simplifying the equation further:
Acceleration = (-11.11 m/s) / 15.0 s
Now we have the acceleration at the moment the train reaches 50.0 km/h. However, finding the radius of the turn requires additional information related to the acceleration.