Which of the following statements does not contain an error?
1. string firstName= in.next();
2. string lastName= in.nextline();
3. system.out.print("\n");
a. 1 only
b. 2 only
c. 3 only
d. 1 and 3 only
e. 2 and 3 only
is the answer 1 and 3
Yes, the answer is d. 1 and 3 only.
Explanation:
1. The statement "string firstName = in.next();" does not contain any errors. It declares a variable called "firstName" of type String and assigns it the value returned by the "next()" method of the "in" object, which is reading input from the user.
2. The statement "string lastName = in.nextline();" contains an error. The correct method to use here is "nextLine()" (with a capital "L") instead of "nextline()". The "nextLine()" method reads the entire line of input, including any spaces, until the user presses Enter.
3. The statement "system.out.print("\n");" does not contain any errors. It uses the correct syntax for printing a newline character ("\n") using the "print()" method of the standard output stream (System.out). This will output a new line on the console.
Yes, the answer is d. 1 and 3 only.
To determine the correct answer, we need to analyze each statement for errors.
1. `string firstName= in.next();`
This statement contains an error. In Java, the keyword `String` should be capitalized, not lowercase `string`. Therefore, statement 1 is incorrect.
2. `string lastName= in.nextline();`
This statement also contains an error. The method should be `nextLine()` instead of `nextline()`. Additionally, the keyword `String` should be capitalized. Therefore, statement 2 is incorrect.
3. `system.out.print("\n");`
This statement does not contain any errors. It correctly uses the `System.out.print()` method to print a newline character ("\n"). Therefore, statement 3 is correct.
Based on our analysis, statements 1 and 2 contain errors, while statement 3 does not. Hence, the correct answer is d. 1 and 3 only.