Mathematics Trigonometry Trigonometric Identities
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prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
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To prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2, we will follow the steps you
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good start LS = sinx/cosx + 1/cosx = (sinx + 1)/cosx multiply top and bottom by (sinx - 1)/(sinx -
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Prove each idenity. 1+1/tan^2x=1/sin^2x 1/cosx-cosx=sinxtanx 1/sin^2x+1/cos^2x=1/sin^2xcos^2x 1/1-cos^2x+/1+cosx=2/sin^2x and
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Sure, I'll walk you through the steps to prove each of the identities. Let's start with the first
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i will do the first one 1+1/tan^2x=1/sin^2x LS = 1 + 1/(sin^2x/cos^2x) = 1 + cos^2x/sin^2x = (sin^2x
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To prove the given identities, we'll need to manipulate and simplify the expressions step-by-step.
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To continue proving the trigonometric identity, we can simplify the expression obtained so far:
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I need to prove equality. a) (sina + cosa)^2 -1 / ctga - sinacosa = 2tg^2a b) (sin^2x/sinx-cosx) - (sinx+cosx/tg^2x+1) = sinx +
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a) LS = [sin^2a + 2sinacosa + cos^2a - 1] / [ cosa/sina - sinacosa] = [1 + 2sinacosa -1] / [ (cosa -
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you must have a typo in A since the left side equals 1 for B multiply the left side by
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To simplify the expression cos(x-y)+cos(x+y)/cosx, you can follow these steps: Step 1: Use the
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a) RS = sin^2x/cos^2x = LS b) LS = sinx/cos^2x = (sinx/cosx)/cosx = tanx/cosx = RS
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