A warehouse worker pushes a crate along the floor, as shown in the figure below, with a force of F = 10.5 N that points at an angle of θ = 61°. Find the horizontal and vertical components of the force.
F = 10.5N[61o].
Fx = 10.5*Cos61 =
Fy = 10.5*sin61 =
To find the horizontal and vertical components of the force, we need to use trigonometric functions. The horizontal component of the force is the force acting in the x-direction, and the vertical component is the force acting in the y-direction.
Given:
Force, F = 10.5 N
Angle, θ = 61°
To find the horizontal component (F_horizontal):
F_horizontal = F * cos(θ)
To find the vertical component (F_vertical):
F_vertical = F * sin(θ)
Let's calculate these components using the given values:
F_horizontal = 10.5 N * cos(61°)
F_horizontal ≈ 5.37 N
F_vertical = 10.5 N * sin(61°)
F_vertical ≈ 8.94 N
Therefore, the horizontal component of the force is approximately 5.37 N, and the vertical component is approximately 8.94 N.