The larger of two numbers is 8 more than twice the smaller number. If the sum of the two numbers is 113, what is the smaller number?

Ej/Larry/Hannah/John/Beverly/Lyven/Jon/Jonna/Nana ~

Wow!!!

Not only do you seem to have a real identity crisis, you also have no thoughts in your head about any of these math problems. How very sad. =(

@Writeacher, I thought it was the same person.

I gave her a start with some of them, now waiting for her reply.

She won't reply. 12 of these posts in 20 minutes! This type never does. They are mooching for answers, and that's about it. Very sad. =(

Hmmm

Writeteacher practicing presidential tweets :)

No clue what that means. ¯\_(ツ)_/¯

To find the smaller number, we can set up a system of equations based on the given information:

Let's assume that the smaller number is x.
According to the problem, the larger number is 8 more than twice the smaller number, which can be expressed as:
Larger number = 2 * smaller number + 8

The sum of the two numbers is given as 113, which can be written as:
Smaller number + Larger number = 113

Using the equations formed, we can solve for the smaller number:

1) Substitute the expression for the larger number in terms of the smaller number into the second equation:
Smaller number + (2 * smaller number + 8) = 113

2) Combine like terms:
3 * smaller number + 8 = 113

3) Subtract 8 from both sides of the equation:
3 * smaller number = 113 - 8
3 * smaller number = 105

4) Divide both sides of the equation by 3 to solve for the smaller number:
smaller number = 105 / 3
smaller number = 35

Therefore, the smaller number is 35.