Mary is 3 times older then nandhini after 10 years the sum of their ages will be 80.find their present ages.
Nadhini's age —> x
Mary's age —> 3x
3x+10 + x+10 = 80
4x = 60
x = 15
Let's assume that Nandhini's present age is represented by "x".
According to the given information, Mary is 3 times older than Nandhini, which means that Mary's present age is 3x.
After 10 years, Nandhini's age will be x + 10, and Mary's age will be 3x + 10.
The sum of their ages after 10 years is 80. So, we can write the equation:
(x + 10) + (3x + 10) = 80
Simplifying the equation:
4x + 20 = 80
Subtracting 20 from both sides:
4x = 60
Dividing both sides by 4:
x = 15
Therefore, Nandhini's present age (x) is 15 years old.
To find Mary's present age, we substitute the value of x into the expression 3x:
Mary's present age = 3 * 15 = 45 years old
So, Nandhini's present age is 15 years old, and Mary's present age is 45 years old.
To find Mary and Nandhini's present ages, let's represent their ages as variables.
Let's assume Mary's present age is represented by "M" and Nandhini's present age is represented by "N".
According to the given information, Mary is 3 times older than Nandhini: M = 3N.
After 10 years, Mary will be M + 10 years old, and Nandhini will be N + 10 years old.
The sum of their ages after 10 years will be 80: (M + 10) + (N + 10) = 80.
Now let's substitute the value of M from the first equation into the second equation:
(3N + 10) + (N + 10) = 80.
Simplifying the equation:
4N + 20 = 80.
Subtracting 20 from both sides:
4N = 60.
Dividing both sides by 4:
N = 15.
Now substitute the value of N back into the first equation to find M:
M = 3N = 3(15) = 45.
Therefore, Mary's present age is 45 and Nandhini's present age is 15.