3. 0.1825 g of Fe(NH4)2(SO4)2•6H2O is dissolved in 250.00 mL of solution; this is Solution A. 5.00 mL of Solution A is transferred to another flask, and it is diluted to a total of 100.0 mL to make another solution, which is Solution B. Next, 3.00 mL of Solution B is diluted to a total of 10.0 mL to make Solution C.

Question

3. 0.1825 g of Fe(NH4)2(SO4)2•6H2O is dissolved in 250.00 mL of solution; this is Solution A. 5.00 mL of Solution A is transferred to another flask, and it is diluted to a total of 100.0 mL to make another solution, which is Solution B. Next, 3.00 mL of Solution B is diluted to a total of 10.0 mL to make Solution C.

a) what is the molar concentration of Solution A?

b) what is the molar concentration of Solution B?

c) what is the molar concentration of Solution C?

Answer 1

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Answer 2

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Answer 3

To find the molar concentration of each solution, we need to calculate the number of moles of the solute present in each solution and then divide it by the volume of the solution.

a) Molar concentration of Solution A:
1. Calculate the number of moles of Fe(NH4)2(SO4)2•6H2O in Solution A:
- Mass of Fe(NH4)2(SO4)2•6H2O = 0.1825 g
- Molar mass of Fe(NH4)2(SO4)2•6H2O = 392.14 g/mol
- Moles of Fe(NH4)2(SO4)2•6H2O = (0.1825 g) / (392.14 g/mol)

2. Calculate the molar concentration of Solution A:
- Volume of Solution A = 250.00 mL = 0.25000 L
- Molar concentration (Molarity) of Solution A = moles / volume in liters

b) Molar concentration of Solution B:
1. Calculate the number of moles of Fe(NH4)2(SO4)2•6H2O in Solution B:
- Transfer volume from Solution A = 5.00 mL = 0.00500 L
- Moles of Fe(NH4)2(SO4)2•6H2O transferred = (Molar concentration of Solution A) * (Transfer volume in liters)

2. Calculate the molar concentration of Solution B:
- Total volume of Solution B = 100.0 mL = 0.1000 L
- Molar concentration of Solution B = moles / volume in liters

c) Molar concentration of Solution C:
1. Calculate the number of moles of Fe(NH4)2(SO4)2•6H2O in Solution C:
- Transfer volume from Solution B = 3.00 mL = 0.00300 L
- Moles of Fe(NH4)2(SO4)2•6H2O transferred = (Molar concentration of Solution B) * (Transfer volume in liters)

2. Calculate the molar concentration of Solution C:
- Total volume of Solution C = 10.0 mL = 0.0100 L
- Molar concentration of Solution C = moles / volume in liters

Plug in the values and perform the calculations to find the molar concentration for each solution.