What would the net ionic equation be for :
HBr (aq) + KOH (aq) = KBr + H2O
OH-(aq) + H+(aq) → H2O(l)
The net ionic equation is
H^+ + OH^- ==> H2O
K^+ and Bar^- are common to both sides and cancel.
well KBr is likely to be aqueous and ionized, if it is not then you have KBr solid and not the ions on the right.
H+ + Br- + K+ + OH- --> K+ + Br- + H2O
What is the spector ions
To determine the net ionic equation for a chemical reaction, you need to first write the balanced molecular equation, then break down the reactants and products into ions, and finally omit the spectator ions to form the net ionic equation.
Let's start by writing the balanced molecular equation for the reaction:
HBr(aq) + KOH(aq) → KBr(aq) + H2O(l)
Next, let's break down the reactants and products into their respective ions:
HBr(aq) → H+(aq) + Br-(aq)
KOH(aq) → K+(aq) + OH-(aq)
KBr(aq) → K+(aq) + Br-(aq)
H2O(l) → H+(aq) + OH-(aq)
Now we can write the complete ionic equation by including all the dissolved ions:
H+(aq) + Br-(aq) + K+(aq) + OH-(aq) → K+(aq) + Br-(aq) + H2O(l)
In the next step, we need to identify which ions are spectator ions. Spectator ions are those that appear on both sides of the equation and do not participate in the chemical reaction. In this case, the K+(aq) and Br-(aq) ions appear on both sides.
Therefore, we can omit the spectator ions, leaving us with the net ionic equation:
H+(aq) + OH-(aq) → H2O(l)
So, the net ionic equation for the reaction of HBr(aq) and KOH(aq) is:
H+(aq) + OH-(aq) → H2O(l)