A motor car of mass 30kg,moving with a velocity of 10m/s. by the application of brakes,it was brought to rest at a distance of 25meters. Find the average force.
force*distance=1/2 m v^2
force=.5*30*100/50 N
a motor car of mass 30kg moving with a velocity of 10m/S by the application of breakes is brought to rest in a distance of 20m. Find the average price
A motor car of mass 30kg moving with a velocity of 10m/s by the application of breaks is bought to rest by distance of 25meters find the average force
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Home work
To find the average force, we can use the work-energy principle, which states that the work done on an object is equal to its change in kinetic energy. In this case, the work done on the car can be calculated as the force applied multiplied by the distance over which the force is applied.
The change in kinetic energy of the car can be calculated by subtracting the final kinetic energy from the initial kinetic energy. Since the car comes to rest, the final kinetic energy is zero.
Kinetic energy (KE) = (1/2) * mass * velocity^2
KE(initial) = (1/2) * (30 kg) * (10 m/s)^2
KE(initial) = 1500 J
Since the final kinetic energy is zero, the change in kinetic energy is:
ΔKE = KE(final) - KE(initial)
ΔKE = 0 - 1500 J
ΔKE = -1500 J
Now, we know that work done (W) is equal to the change in kinetic energy (ΔKE):
W = ΔKE
Force * distance = -1500 J
To find the average force, we need to divide both sides of the equation by the distance (25 m):
Force = -1500 J / 25 m
Force = -60 N
The negative sign indicates that the force is in the opposite direction of motion. Thus, the average force applied by the brakes to bring the car to rest is 60 N.