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Professor Beaker has a 50-milliliter solution containing 60% acid. How many milliliters of pure water should he add to this solution to produce a solution containing 40% acid?

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    see related questions below.

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    I've tried looking at similar problems but I'm still confused.

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    the amount of acid in the parts must add up to the amount in the final mix. If x ml of water (0% acid) are added, then you need

    .60*50 + 0x = .40(50+x)

    Now just solve for x. This assume you know what "%" means ...

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