Maths
posted by Jay .
A building, B, is observed from two points P and Q which are 250 m apart. The angles PQB and QPB are found to be 67 degrees and 73 degrees respectively. What is the distance, to the nearest metre, of P from the building?

angle B is 1806773 = 40°
Now, using the law of sines
250/sin40° = PB/sin67°
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