CaCl2 reacts with AgNO3 in aqueous solutions to produce a precipitate of AgCl that can be filtered and
weighed. The balanced equation for the reaction is:
CaCl2 (aq) + 2 AgNO3 (aq) → 2 AgCl (s) + Ca(NO3)2 (aq)
To balance the equation for the reaction between CaCl2 and AgNO3, follow these steps:
Step 1: Write the unbalanced equation:
CaCl2 (aq) + AgNO3 (aq) → AgCl (s) + Ca(NO3)2 (aq)
Step 2: Balance the equation by making sure that the number of each type of atom is the same on both sides of the equation. Start by balancing the most complex molecule first, in this case, AgNO3.
CaCl2 (aq) + 2 AgNO3 (aq) → AgCl (s) + Ca(NO3)2 (aq)
Step 3: Balance the number of chlorine (Cl) atoms by adding a coefficient of 2 in front of the CaCl2:
2 CaCl2 (aq) + 2 AgNO3 (aq) → AgCl (s) + Ca(NO3)2 (aq)
Now, the equation is balanced.
The balanced equation is:
2 CaCl2 (aq) + 2 AgNO3 (aq) → 2 AgCl (s) + Ca(NO3)2 (aq)
To balance the equation, we need to make sure that the number of each type of atom is the same on both sides of the equation.
The equation given is:
CaCl2 (aq) + 2 AgNO3 (aq) → 2 AgCl (s) + Ca(NO3)2 (aq)
We can start by balancing the calcium (Ca) atoms. There is one Ca on the left side and one Ca on the right side, so this is already balanced.
Next, let's balance the chlorine (Cl) atoms. There are two Cl atoms on the left side from CaCl2 and two Cl atoms on the right side from 2 AgCl. This means the Cl atoms are already balanced as well.
Now let's move on to balancing the silver (Ag) atoms. There are two Ag atoms on the left side from 2 AgNO3 and two Ag atoms on the right side from 2 AgCl. So the Ag atoms are also balanced.
Lastly, we need to balance the nitrogen (N) and oxygen (O) atoms. There are two NO3 groups on the left side from 2 AgNO3 and one NO3 group on the right side from Ca(NO3)2. This means we need to add a coefficient of 2 in front of Ca(NO3)2 to balance the N and O atoms.
The final balanced equation is:
CaCl2 (aq) + 2 AgNO3 (aq) → 2 AgCl (s) + Ca(NO3)2 (aq)