The volume of a H2SO4 solution to 36.75% by weight of density 1, 8g/cm ^ 3, necessary to prepare 500 ml of a solution 3N of sulphuric acid is approximately:
What is the molarity of the initial H2SO4? That's
1.8 g/mL x 1000 mL x 0.3675 x (1/98) = y
N = 2*M
Then mL1 x N1 = mL2 x N2
mL1 x yN = 500 x 3N
Substitute and solve for mL1.
To find the volume of the H2SO4 solution necessary to prepare the desired solution, we need to use the information about the concentration and density of the solution.
Step 1: Calculate the molar mass of H2SO4
The molar mass of H2SO4 is:
(2 × atomic mass of H) + atomic mass of S + (4 × atomic mass of O)
= (2 × 1) + 32 + (4 × 16)
= 2 + 32 + 64
= 98 g/mol
Step 2: Calculate the concentration of the desired solution in moles/L (Molarity)
The solution concentration is given as 3N (Normality), which can be converted to moles/L (Molarity) using the following equation:
Molarity = Normality × molar mass
Given that the Normality (N) is 3, the Molarity (M) can be calculated as:
Molarity = 3 × 98 g/mol
= 294 g/L
Step 3: Calculate the mass of H2SO4 required
To calculate the mass, we can use the formula:
Mass = Volume × Density
Given that the volume is 500 mL (or 0.5 L) and the density is 1.8 g/cm^3, we can calculate the mass as:
Mass = 0.5 L × 1.8 g/cm^3 × 1000 g/L
= 900 g
Step 4: Calculate the mass of H2SO4 in the solution
The mass percent of H2SO4 is given as 36.75%. This means that 100 g of the solution contains 36.75 g of H2SO4.
Let the mass of the H2SO4 solution be x g.
Therefore, (36.75/100) × x = mass of H2SO4 required (900 g)
Solving for x:
(36.75/100) × x = 900
x = (900 × 100) / 36.75
x ≈ 2452.38 g
Step 5: Calculate the volume of the H2SO4 solution
Finally, to find the volume of the H2SO4 solution, we need to calculate the volume using the density. Rearranging the formula mass = volume × density, we get:
Volume = Mass / Density
Volume = 2452.38 g / 1.8 g/cm^3
Volume ≈ 1362.43 cm^3 or mL
Therefore, the approximate volume of the H2SO4 solution necessary to prepare 500 mL of a 3N sulphuric acid solution is approximately 1362.43 mL or cm^3.