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IF 8.5g of KOH powder are placed in 100g of water at room temperature of 20degree Celsius, what is the final temperature of the solution.
KOH K+OH H=-57.61 KJ/MOL KOH

  • Science -

    if the heat of solution is -57.62kj per mole, the question is what portion of a mole is 8.5 grams?
    8.5/56.1=...
    Now the sum of heats gained is zero.
    8.5/56.1*57.64+100g* 4.18kj/kg*(tf-20)=0

    tf-20= 8.7/.418

    solve for temp final tf. Check my work

  • Science -

    when calculating the heat gained by solution, the total mass will be 108.5 gm not 100gm. Since there was 8.5g of KOH added to water.

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