Area of rectangular hall is

165sq.m.if the length is 4m more than its breadth.find the length and breadth of the hall

Good

15m and 11m

To find the length and breadth of the hall, we'll first set up equations based on the given information.

Let's assume the breadth of the hall is "x" meters.

According to the problem, the length of the hall is 4 meters more than its breadth. So, the length of the hall can be expressed as "x + 4" meters.

The area of a rectangle can be calculated by multiplying its length by its breadth. In this case, the area is given as 165 square meters.

So, the equation we can form is:

x * (x + 4) = 165

Now, let's solve this equation to find the values of x (breadth) and (x + 4) (length).

Expanding the equation, we get:

x^2 + 4x = 165

Rearranging the equation to make it a quadratic equation:

x^2 + 4x - 165 = 0

Next, we can either factorize the equation or use the quadratic formula to find the values of x.

Using factorization, the equation can be written as:

(x + 15)(x - 11) = 0

Setting each factor equal to zero gives us:

x + 15 = 0 or x - 11 = 0

Solving these equations, we find two possible values for x:

x = -15 or x = 11

Considering that we're talking about measurements, a negative breadth doesn't make sense. Therefore, we choose x = 11 as the breadth of the hall.

To find the length, we substitute x = 11 into the expression "x + 4":

Length = 11 + 4 = 15

Therefore, the breadth of the hall is 11 meters and the length is 15 meters.

well, 165 = 11*15 ...

Cccbn