. Using I2 (aq)+ 2S2O3=> S4O6 (aq)+ 2I(aq) calculate the number of moles of molecular iodine. Given that there are 0.004328482 Moles of Na2S2O3.

can someone please help i have no idea how to do this question for my lab!!! if possible please explain with steps.

umm yeah i need help with that too

To calculate the number of moles of molecular iodine (I2), we can use stoichiometry to determine the ratio of moles between I2 and Na2S2O3.

First, we need to balance the given chemical equation:

2I2(aq) + 2Na2S2O3(aq) → 2NaI(aq) + Na2S4O6(aq)

From the balanced equation, we can see that the coefficient ratio between I2 and Na2S2O3 is 2:2 (1:1). Therefore, for every 2 moles of Na2S2O3, there are 2 moles of I2.

Given that there are 0.004328482 moles of Na2S2O3, we can set up a proportion using the ratio we determined:

(2 moles of I2 / 2 moles of Na2S2O3) = (X moles of I2 / 0.004328482 moles of Na2S2O3)

By solving the proportion, we can find the number of moles of I2:

2/2 = X/0.004328482

Simplifying the equation:

1 = X/0.004328482

Multiplying both sides by 0.004328482:

X = 0.004328482 moles of I2

Therefore, the number of moles of molecular iodine (I2) is 0.004328482 moles.