Given the parent genotype AaBbCCDDEe, what is the probability of each of these gametes forming?
a) ABCDE
b) either ABCDE or abCDE
Would the answer for a) be 1/8 and for b) be 1/2?
Yes, exactly as I did for you earlier.
Thank you.
Let's break it down step-by-step:
Step 1: Determine the number of possible gametes
The genotype AaBbCCDDEe has 2 possible alleles for each gene (A or a, B or b, C or C, D or D, E or e). Therefore, there are 2 x 2 x 2 x 2 x 2 = 32 possible combinations of alleles in the gametes.
Step 2: Calculate the probability of each gamete forming
a) To determine the probability of forming the specific gamete ABCDE, you need to know the alleles present in each gene. From the parent genotype AaBbCCDDEe, we can see that A, B, C, D, and E are the dominant alleles.
- The probability of getting A is 1, since the parent has an A allele.
- The probability of getting B is 1, since the parent has a B allele.
- The probability of getting C is 1, since the parent has a C allele.
- The probability of getting D is 1, since the parent has a D allele.
- The probability of getting E is 1, since the parent has an E allele.
Therefore, the probability of forming the gamete ABCDE is 1 x 1 x 1 x 1 x 1 = 1.
b) To calculate the probability of forming either ABCDE or abCDE, we need to consider the possible combinations for the first gene, which is A or a. Since there are two possible alleles for the first gene, there are two scenarios to consider:
- Scenario 1: A is chosen for the first gene.
The probability of getting A for the first gene is 1/2. From the remaining four genes (B, C, D, and E), we have already established that the probability of getting the desired alleles is 1. Therefore, the probability of forming the gamete ABCDE in this scenario is (1/2) x 1 x 1 x 1 x 1 = 1/2.
- Scenario 2: a is chosen for the first gene.
The probability of getting a for the first gene is 1/2. From the remaining four genes (B, C, D, and E), we have already established that the probability of getting the desired alleles is 1. Therefore, the probability of forming the gamete abCDE in this scenario is (1/2) x 1 x 1 x 1 x 1 = 1/2.
To calculate the overall probability of forming either ABCDE or abCDE, we sum up the probabilities from both scenarios:
(1/2) + (1/2) = 1/2.
Therefore, the probability of forming either ABCDE or abCDE is 1/2.
In conclusion:
a) The probability of forming the gamete ABCDE is 1.
b) The probability of forming either ABCDE or abCDE is 1/2.
To calculate the probability of a specific gamete forming, we need to consider the multiplication rule of probability. According to Mendelian genetics, during gamete formation, alleles independently assort to form different combinations.
In the given parent genotype AaBbCCDDEe, there are 5 different gene loci, represented by letters A, B, C, D, and E. Each gene locus has two alleles, except for locus C, which has only one allele.
a) To calculate the probability of the gamete ABCDE forming, we need to determine the probability of each allele being included in the gamete.
Probability of allele A being included: 1 (since parent genotype has genotype Aa, meaning one A allele is present)
Probability of allele B being included: 1 (since parent genotype has genotype Bb, meaning one B allele is present)
Probability of allele C being included: 1 (since parent genotype has genotype CC, meaning both alleles are C)
Probability of allele D being included: 1 (since parent genotype has genotype DD, meaning both alleles are D)
Probability of allele E being included: 1 (since parent genotype has genotype Ee, meaning one E allele is present)
By multiplying all these probabilities, we get:
1 * 1 * 1 * 1 * 1 = 1
Therefore, the probability of the gamete ABCDE forming is 1.
b) To calculate the probability of either the gamete ABCDE or abCDE forming, we need to consider the probability of allele A being present in both uppercase A and lowercase a forms.
Probability of allele A being included: 1 (since parent genotype has genotype Aa, meaning both A alleles are present)
Probability of allele B being included: 1 (since parent genotype has genotype Bb, meaning one B allele is present)
Probability of allele C being included: 1 (since parent genotype has genotype CC, meaning both alleles are C)
Probability of allele D being included: 1 (since parent genotype has genotype DD, meaning both alleles are D)
Probability of allele E being included: 1 (since parent genotype has genotype Ee, meaning one E allele is present)
By multiplying all these probabilities, we get:
1 * 1 * 1 * 1 * 1 = 1
Therefore, the probability of either the gamete ABCDE or abCDE forming is also 1.
So, the answer for both a) and b) is 1, not 1/8 and 1/2 respectively.