3ca(s) + 2H3PO4(aq) -> Ca3(PO4)2(aq)+3H2(g)
1)a reaction between calcium and a solution of 1.2moldm-3 phosphoric acid produced 3 mol of H2 gas.
a) Minimum volume of phosphoric acid would have been needed for reaction: I got 1.6cm3
b)Mass of calcium added tpo this acid? I got 120.3
c)Maximum amount of calcium phosphate that could be obtained by thi sprocess???
Please help with c and tell me f a and b are right
Forgot to post the other question for thisequation:
2)
2.00g of calcium was added to 500cm3 of 0.1moldm-3 and the solution was left until all the effervescence had stopped.
a) What volume of 2 moldm-3 NaOH solution would be needed to neutralise th remaining H3PO4?
PLease help showing all working out
does effervescence affect the calculations?
To calculate the maximum amount of calcium phosphate that could be obtained by this process, you need to use stoichiometry. Start by balancing the equation:
3Ca(s) + 2H3PO4(aq) -> Ca3(PO4)2(aq) + 3H2(g)
From the balanced equation, you can see that for every 3 moles of calcium (Ca), you would obtain 1 mole of calcium phosphate (Ca3(PO4)2).
Since you provided the information that 3 moles of H2 gas were produced, you can work backward to find the moles of calcium used:
3 moles H2 gas x (1 mole Ca / 3 moles H2 gas) = 1 mole Ca
So, 1 mole of calcium was used in the reaction.
To find the maximum amount of calcium phosphate, you need to convert moles of calcium to moles of calcium phosphate:
1 mole Ca x (1 mole Ca3(PO4)2 / 3 moles Ca) = 0.333 mole Ca3(PO4)2
Therefore, the maximum amount of calcium phosphate that could be obtained by this process is 0.333 moles.
Now let's check the answers for a and b:
a) The minimum volume of phosphoric acid needed for the reaction can be calculated using the stoichiometry of the balanced equation. However, the concentration of the phosphoric acid solution (1.2 moldm-3) and 1.6 cm3 provided don't give enough information to directly calculate the volume of the acid. Therefore, it's not possible to determine if your answer of 1.6 cm3 is correct without additional information.
b) The mass of calcium added to the acid can be determined once the number of moles of calcium is known. Since we found that 1 mole of calcium was used in the reaction, you can calculate the mass of calcium using its molar mass.
Mass = Moles x Molar mass
Mass = 1 mole x 40.078 g/mol (molar mass of calcium)
Therefore, the mass of calcium added would be 40.078 grams.
In summary:
a) The minimum volume of phosphoric acid cannot be determined without more information.
b) The mass of calcium added is 40.078 grams.
c) The maximum amount of calcium phosphate that could be obtained is 0.333 moles.