1 mole of each of the following substances is dissolved in 1 L of water. Order them from most ions (1.) to least ions (4.) in solution.
CH2CH2-OH
ZnCl2
H2SO3
NaNO3
I still want to know what your problem is in doing this.
To determine the number of ions in each substance, we need to understand how these compounds dissociate in water.
1. CH2CH2-OH:
This compound is known as ethanol, and it does not dissociate to form ions in water. Ethanol remains as intact molecules, so it does not contribute any ions to the solution. Therefore, it has no ions in solution.
2. ZnCl2:
ZnCl2 dissociates in water to form Zn2+ cations and two Cl- anions for each unit of ZnCl2. Since there are two chloride ions formed for each unit of ZnCl2, this compound produces a total of three ions in solution.
3. H2SO3:
H2SO3 is known as sulfurous acid, which can donate two hydrogen ions (H+) in an aqueous solution. Therefore, it dissociates into two H+ cations and one SO3^2- anion, resulting in three ions in solution.
4. NaNO3:
NaNO3, or sodium nitrate, dissociates completely in water to form one sodium ion (Na+) and one nitrate ion (NO3-) for each unit of NaNO3. So, this compound produces a total of two ions in solution.
Based on this information, the order of the substances from most ions (1) to least ions (4) in solution is as follows:
1. H2SO3 (3 ions)
2. ZnCl2 (3 ions)
3. NaNO3 (2 ions)
4. CH2CH2-OH (0 ions)