Algebra 2
posted by Kk
Solve the system by substitution
2xy+z=4
z=5
2x+3yz=10
I think the answer is (8,7,5)
But can someone tel me the right one and explain I’m so lost

Scott
2x  y + 5 = 4 ... 2x  y = 9
2x + 3y  5 = 10 ... 2x + 3y = 5
adding equations (to eliminate x)
... 2y = 14
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