Ramu is now half old as as his father . twenty years ago Ramu's father was six times ramu's age. what are their ages
Ummmhh,
if you are half as old as your sister, wouldn't your sister be twice as old?? . I defined it the way I did to avoid fractions.
What does 6(x-20) mean?
Does it not say 6 times (the son's age) ??
2x-20 = 6(x-20)
2x-20 = 6x - 120
-4x = -100
x = 25
So the son is now 25 and the father is 2x or 2(25) or 50
check:
how old was the son 20 years ago? He was 5
how old was the father 20 years ago? He was 30
Was he not 6 times as old as his son ????
6 times 5 = 30
but its given six times . explain me more better
To find the ages of Ramu and his father, we'll create equations based on the given information and then solve them.
Let's assume Ramu's current age is "x" and his father's current age is "y".
According to the first statement: "Ramu is now half as old as his father," we can write the equation:
x = (1/2) * y
Next, let's consider the second statement: "Twenty years ago Ramu's father was six times Ramu's age." We need to take into account that 20 years have passed, so we'll subtract 20 from both ages. The equation becomes:
y - 20 = 6 * (x - 20)
Now we have a system of two equations:
x = (1/2) * y
y - 20 = 6 * (x - 20)
To solve this system, we can substitute the first equation into the second equation:
y - 20 = 6 * ((1/2) * y - 20)
Now let's simplify the equation:
y - 20 = 3y - 120
2y = 100
y = 50
Substituting the value of y into the first equation, we can find x:
x = (1/2) * 50
x = 25
Therefore, Ramu's current age is 25 years old, and his father's current age is 50 years old.
So the father is now twice as old as his son
son's age ---- x
father's age ---- 2x
Twenty years ago :
son's age = x-20
father's age = 2x-20
2x-20 = 6(x-20)
solve for x, etc