na2s(aq)+Cu(no3)2(aq)→nano3(aq)+Cus(s) net ionic equation?
To obtain the net ionic equation, we need to first write down the balanced chemical equation for the given reaction:
Na2S(aq) + Cu(NO3)2(aq) → NaNO3(aq) + CuS(s)
Next, we will break down the equation into its ionic form, indicating the state of each species:
2Na⁺(aq) + S²⁻(aq) + Cu²⁺(aq) + 2NO₃⁻(aq) → 2Na⁺(aq) + 2NO₃⁻(aq) + CuS(s)
Now, we can identify the spectator ions, which are ions that do not participate in the actual chemical reaction. In this case, the spectator ions are Na⁺ and NO₃⁻.
Finally, we can write the net ionic equation by removing the spectator ions from the equation:
S²⁻(aq) + Cu²⁺(aq) → CuS(s)
Therefore, the net ionic equation for the given reaction is S²⁻(aq) + Cu²⁺(aq) → CuS(s).
To find the net ionic equation, we first start by writing the balanced chemical equation:
Na2S(aq) + Cu(NO3)2(aq) → NaNO3(aq) + CuS(s)
Next, we can identify the soluble compounds and break them apart into their respective ions:
Na2S(aq) → 2Na+ (aq) + S2- (aq)
Cu(NO3)2(aq) → Cu2+ (aq) + 2NO3- (aq)
NaNO3(aq) → Na+ (aq) + NO3- (aq)
Since CuS is insoluble, it remains as a solid:
CuS(s)
Now, we can write the net ionic equation by removing the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction):
Net ionic equation: S2- (aq) + Cu2+ (aq) → CuS(s)
Therefore, the net ionic equation for the given reaction is S2- (aq) + Cu2+ (aq) → CuS(s).
You would do well to find the caps key on your keyboard and use it. What do you not understand about this.
Here are the steps.
1. Write the molecular equation and balance it. You haven't balanced it yet.
2. Convert to the full ionic equation using the following rules:
a. Write as a molecule gases.
b. Write as a molecule insoluble materials.
c. Write as a molecule weak electrolytes; i.e., H2O, weak acid, weak bases.
d. Cancel any ions that appear on both the left and right sides of the equation.
e. What's left is the net ionic equation.