A force of 0.8N stretches an elastic materials by2cm. Find the elastic constant of the material.
f=kx
k=f/x=.8/.02 N/m=40N/m
Thank you
To find the elastic constant of the material, we need to use Hooke's Law, which states that the force applied to an elastic material is directly proportional to the extension or deformation produced.
Hooke's Law can be expressed as:
F = k * x
where:
F is the force applied (0.8N in this case)
k is the elastic constant (what we want to find)
x is the extension or deformation produced (2cm in this case)
We can rearrange the equation to solve for the elastic constant:
k = F / x
k = 0.8N / 2cm
However, it's important to note that we need to ensure the units are consistent. In this case, we need to convert cm to meters since the SI unit of force is Newtons and the SI unit of length is meters.
1 cm = 0.01 meters
k = 0.8N / (2 * 0.01m)
k = 0.8N / 0.02m
k = 40 N/m
So, the elastic constant of the material is 40 N/m.