Outline how a 250cm^3 of 0.10mol/dm^3 hydrochloric acid could be prepared from 100cm^3 of a 2.0mol/dm^3 stock solution
cc x M = cc x M
250 x 0.10 = cc x 2.0
Solve for cc, pipet that amount from the 2.0 M stuff into a 250 cc container, add water to the mark, shake, stopper.