Three resistors of resistance 50,30,40 ohms are connected in series across 100V suppliers.
(I).Draw circuit
(II).Calculate the total resistance.
(III).Total current flowing through the circuit.
(v). Voltage drop across each resistor.
total R = 50 + 40 + 30
current = voltage / total R
v drop = current * resistance
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(I). To draw the circuit, you will need to connect the three resistors in series across the 100V supply.
---(R1 = 50Ω)---(R2 = 30Ω)---(R3 = 40Ω)---
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100V
This is a simple series circuit, where the resistors are connected one after another along a single path.
(II). To calculate the total resistance, you simply add up the individual resistances. In this case, the total resistance (RT) is:
RT = R1 + R2 + R3
RT = 50Ω + 30Ω + 40Ω
= 120Ω
Hence, the total resistance is 120Ω.
(III). To calculate the total current flowing through the circuit, you can use Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R). In this case, since the resistors are in series, the current is the same across all of them.
I = V / RT
I = 100V / 120Ω
≈ 0.8333 A
The total current flowing through the circuit is approximately 0.8333 A.
(v). To find the voltage drop across each resistor, you can use Ohm's Law again. Since the current is the same across each resistor in a series circuit, the voltage drop across each resistor is directly proportional to its resistance.
VR1 = I * R1
VR2 = I * R2
VR3 = I * R3
VR1 = 0.8333 A * 50Ω
= 41.67 V
VR2 = 0.8333 A * 30Ω
= 25 V
VR3 = 0.8333 A * 40Ω
= 33.33 V
Therefore, the voltage drop across each resistor is approximately: VR1 = 41.67 V, VR2 = 25 V, and VR3 = 33.33 V.