Four point masses are placed at the corner of a square of side 2m .find the centre of mass of the system w.r.t the centre of square?
To find the center of mass of the system with respect to the center of the square, we need to consider the mass and location of each of the four point masses.
Let's label the four masses as M1, M2, M3, and M4. We assume that all four masses are equal.
Since the point masses are placed at the corners of a square, the center of the square is also the center of symmetry. This means that the center of mass of the system will coincide with the center of the square.
Since all the masses are equal, the center of mass of the system will be at the center of the square, which is also the point of intersection of the diagonals.
The diagonals of the square intersect at a right angle, and the length of each diagonal is equal to 2m√2, which is obtained from Pythagoras' theorem.
So, the center of mass of the system with respect to the center of the square is at the intersection point of the diagonals, which bisect each other.