Calculate the molarity of a solution prepared by dissolving 13.6 g ZnCl2 in 432 g H2O. Assume that the density of the solution is 1.00 g/mL. The molar mass of ZnCl2 is 136.29 g/mol and the molar mass of H2O is 18.02 g/mol.

mols ZnCl2 = grams/molar mass = ?

volume H2O = mass H2O/density H2O = ?
M = mols/L.

From the problem it sounds like you want molality.

To calculate the molarity of a solution, you need to know the moles of solute (ZnCl2) and the volume of the solution (in liters). Here's how you can find the molarity step by step:

1. Calculate the moles of ZnCl2:
- Convert the mass of ZnCl2 to moles by dividing it by the molar mass of ZnCl2:
moles of ZnCl2 = 13.6 g / 136.29 g/mol = 0.1 mol

2. Calculate the volume of the solution in liters:
- Convert the mass of H2O to volume by dividing it by the density of the solution:
volume of H2O = 432 g / 1.00 g/mL = 432 mL = 0.432 L

3. Calculate the molarity (M) of the solution:
- Molarity is defined as moles of solute divided by volume of solution in liters:
Molarity = moles of ZnCl2 / volume of solution
M = 0.1 mol / 0.432 L ≈ 0.23 M

Therefore, the molarity of the solution prepared by dissolving 13.6 g ZnCl2 in 432 g H2O is approximately 0.23 M.