Algebra 2
posted by Janet
How do I find a and b given the equation ax^2 + bx 4 and a vertex point of (1,6)?

Scott
the vertex is on the axis of symmetry
x = b / 2a ... 2a =  b
plugging the point into the main equation
... 6 = a(1^2) + b(1)  4
... 2 = a + b
use the two equations to find a and b
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