# tangential acceleration??

posted by anonymous

An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. What is the tangential acceleration of a point 9.50 cm from the axis of rotation? Your answer should be given in m/sec squared.

Tangential acceleration = angular acceleration * radius

How would I find this?

1. Scott

angular acceleration = (1E5 * 2 * π) / (2 * 60)

the radius is ... .095 m

2. anonymous

That gives me 497.42...it's wrong

3. Damon

change in angular velocity
= 10^5 * 2 pi radians/60 seconds

change in time = 2 * 60 seconds
so I get
10^5 * 2 *pi /(120*60)

multiply that by .095
or just divide previous answer by 60

4. Scott

is it a significant figure issue?

but there is only one in the rpm data

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