posted by anonymous .
An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. What is the tangential acceleration of a point 9.50 cm from the axis of rotation? Your answer should be given in m/sec squared.
Tangential acceleration = angular acceleration * radius
How would I find this?
angular acceleration = (1E5 * 2 * π) / (2 * 60)
the radius is ... .095 m
That gives me 497.42...it's wrong
change in angular velocity
= 10^5 * 2 pi radians/60 seconds
change in time = 2 * 60 seconds
so I get
10^5 * 2 *pi /(120*60)
multiply that by .095
or just divide previous answer by 60
is it a significant figure issue?
you've got 5 in your answer
but there is only one in the rpm data