posted by Abhay

n+3P6 : n+2P4 = 14 : 1. Find 'n' .

  1. Steve

    n+3P6 = (n+3)(n+2)(n+1)(n)(n-1)(n-2)
    n+2P4 = (n+2)(n+1)(n)(n-1)

    (n+3)(n-2) = 14

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